Given ab bc and ao oc
WebNov 26, 2024 · ABCD is a trapezium with AD ∥ BC and AD = 4cm. If the diagonals AC and BD intersect each other at O such that AO/OC = DO/OB =1/2, then BC = (a) 6cm (b) 7cm (c) 8cm (d) 9cm cbse class-10 1 Answer +1 vote answered Nov 26, 2024 by Ankurgupta (53.8k points) selected Nov 28, 2024 by AmitMukherjee Best answer (c) 8cm In triangles ΔAOD … WebMar 22, 2024 · Δ AOD ≅ Δ BOC (From 1st part) ∠ OAD = ∠ OBC (CPCT) But ∠ OAD & ∠ OBC and these form a pair of alternate angles If a transversal intersects two lines such that pair of alternate interior angles is equal, then lines are parallel. Therefore, AD ∥ BC. Next: Example 2 → Ask a doubt Chapter 7 Class 9 Triangles Serial order wise Examples
Given ab bc and ao oc
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WebAug 9, 2024 · Solution. Given: Consider an arc ACB in which C is mid point of arc ACB and PCQ is the tangent to the circle.. Join AC, BC and AB.. Question. 10 In a figure the common tangents, AB and CD to two ... WebAug 22, 2024 · If D, E, F are mid-points of the sides BC, CA and AB respectively of a ∆ ABC, Prove that AD and FE bisect each other. Answer: Given : D, E, F are mid-points of the sides BC, CA and AB respectively of a ∆ ABC To Prove: AD and FE bisect each other. Const: Join ED and FD Proof : D and E are mid-points of BC and AB respectively (given).
WebIn AOB,∠AOB= 90∘C is a point on AB such that AC = BC join OCSince C is the mid point of hypotenuse of right AOB∴ AC = CB= OC = 6.5cm [Since mid-point of the hypotenuse of … WebAO O C = BO DO ⇒ AO BO = CO DO Hence, proved. Therefore we proved that AO BO = CO DO Suggest Corrections 32 Similar questions Q. ABCD is a trapezium in which AB …
WebJan 31, 2024 · answered in a fig. O is the centre of the circle OC = 5 cm and AB = BC = 2 (under root 5) . Find the length of AC. Advertisement Loved by our community 24 people found it helpful sualiha AO=5cm (radius of the … WebJun 21, 2024 · Given: AB ≅ BC and AO ≅ OC OK − angle bisector of ∠BOC Find: m∠AOK Answers Answer from: roro67 SHOW ANSWER Your answer is: m < AOK = 135° Step …
WebO is any point in the interior of a triangle ABC. Prove that 1. AB + AC > OB + OC 2.AB + BC + CA > OA + OB + OC 3.OA + OB + OC > 1/2 (AB + AC + BC) Solution Given : In …
WebAug 5, 2024 · In the figure, EF AC, BC = 10 cm, AB = 13 cm and EC = 2 cm, find AF. (2014) Solution: BE = BC – EC = 10 – 2 = 8 cm Let AF = x cm, then BF = (13 – x) cm In ∆ABC, EF AC … [Given Question 12. X and Y are points on the sides AB and AC respectively of a triangle ABC such that , AY = 2 cm and YC = 6 cm. Find whether XY … moviehouse \u0026 eatery by cinépolisWeb1. DO = OB, AO = OC 2. heather h morrow crnpWeb8 was given as the length of AB. BO is a radius of the circle and therefore has length of 5. So, AO (which equals AB + BO) is 8 + 5 which is 13. They also had to test whether there was a right angle at point C, so they used the Pythagorean theorem to see whether … moviehouse \u0026 eatery flower moundWebGiven: AB = BC and AO = OC, ОК Z bisector of ZBOC Find: mZAOK В K А C mZAOK Expert Solution. Want to see the full answer? Check out a sample Q&A here. See Solution. Want to see the full answer? See Solutionarrow_forward Check out a sample Q&A here. View this solution and millions of others when you join today! ... Given: AB BC and E is … moviehouse \u0026 eatery by cinepolisWebGiven: In the figure, OA=OC, AB =BC We need to prove that, AOB = 90° (i) In ΔABO and ΔCBO, AB = BC ...[given ] AO = CO ...[ given ] OB = OB ...[ common ] ∴By Side-Side-Side criterion of congruence, we have ΔABO ≅ … heather hoadWebMar 12, 2024 · Step-by-step explanation: Given: BC AD AB = 4cm Diagonals AC and BD intersect at O such that AO/OC = DO/OB =1/2. To find: BC Solution Let BC = m, ∠AOD be x which implies ∠COB = x ∠OAD = y, implies ∠OCB = y CO = 2a implies OA = a ΔOAD ~ ΔOCB (AA similarity) So OA/AD = OC/CB a/4 = 2a/m Therefore m = 2a * 4/a = 8 cm … heather hnatiukWebA, B and C are three points on a circle. Prove that the perpendicular bisectors of AB, BC and CA are concurrent. Answer: Given: A, B, C are 3 points on a circle Construction Draw perpendicular dissector of AB and AC and they meet at a point O. Then join OA, OB and OC. To prove: perpendicular bisector of AB, BC and CA are concurrent. heather hlavka